SOLUTION: Returning to the sports car that accelerates from a standing start to 65 mi/h in 4.61 s, how far does it travel during that run? Express your answer to the nearest ft.

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Question 324532: Returning to the sports car that accelerates from a standing start to 65 mi/h in 4.61 s, how far does it travel during that run? Express your answer to the nearest ft.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
for UNIFORM acceleration ___ average velocity is 65/2 mph or 47.67 ft/sec (approx)

distance = velocity * time = 47.67 * 4.61