SOLUTION: write an equation of an equation of the line that passes through the given point and has the given given slope. write the equation in solpe- intercept form. (3, -9), m=-5

Algebra ->  Test -> SOLUTION: write an equation of an equation of the line that passes through the given point and has the given given slope. write the equation in solpe- intercept form. (3, -9), m=-5       Log On


   



Question 23882: write an equation of an equation of the line that passes through the given point and has the given given slope. write the equation in solpe- intercept form.
(3, -9), m=-5 (-5, -6), m= -3 (4,-2) m= 1/2

(1/3,-5),m=8

Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
Anither way to solve these;
(3,-9) m=-5
Put it in slope-intercept form;
y=-5x-9
You can make a table of values for x and y;
x | y
-----
0 |
1 |
-1|
Solve the equation for y pluging in the values you chose for x;
when x=0;
y=-5(0)-9
y=-9
when x=1;
y=-5(1)-9
y=-14
when x=-1;
y=-5(-1)-9
y=-4
x|y
----
0|-9
1|-14
-1|-4
Now plot these poinnts on the graph and draw your line to connect those.
graph%28+500%2C500%2C+-11%2C+5%2C-17%2C5%2Cy=-5x-9+%29
I will work out the other problems, but then you need ti graph them.
2)(-5,-6) m=-3
y=-3x-6
when x=0
y=-3(0)-6
y=-6
when x=1
y=-3(1)-6
y=-3-6
y=-9
when x=-1
y=-3(-1)-6
y=-3
3)(4,-2) m=1/2
y=1/2x-2
when x=0;
y=1/2(0)-2
y=-2
when x=2;
y=1/2(2)-2
y=-1
when x=4;
y=1/2(4)-2
y=4/2-2
y=2-2
y=0
4)(1/3,-5), m=8
y=8x-5
when x=0
y=8(0)-5
y=-5
when x=1
y=8(1)-5
y=8-5
y=3
when x=2;
y=8(2)-5
y=16-5
y=11
=)