Question 205869: A straight line L passes though the point (0, -1) and is parallel to the straight line y=3x+1.
i. Write down the equation of the straight line L.
ii. Given that L passes through the point (2,b) find the value of b.
Found 2 solutions by Alan3354, RAY100:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A straight line L passes though the point (0,-1) and is parallel to the straight line y=3x+1.
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The slope, m, of the line y=3x+1 is 3.
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i. Write down the equation of the straight line L.
Use (always):
y-y1 = m*(x-x1) (x1,y1) is the point (0,-1)
y+1 = 3x
y = 3x-1 is the line L.
ii. Given that L passes through the point (2,b) find the value of b.
y = 3x-1
x = 2
y = 5 = b
Answer by RAY100(1637)  (Show Source):
You can put this solution on YOUR website! Remember y= mx +b
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y=3x +1,,,,,,m=3,,,,,parallel to this also has m=3
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parallel line,,,,y= 3x +b,,,thru (0,-1),,,,subst
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(-1) = 3(0) +b
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b= -1
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or parallel line (L),,,,y= 3x -1 (i)
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if y=3x-1,,,,thru (2,b),,,,subst
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(b) = 3(2) -1,,,,,b= 5,,,,,(ii)
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