SOLUTION: PQRS is a trapezium where PQ // SR. Given that PQR = SPR= 90˚, PQ = 8.5cm and PR = 12.3 cm. Calculate (a) QR (b) PS (c) The area of the trapezium PQRS.

Algebra ->  Test -> SOLUTION: PQRS is a trapezium where PQ // SR. Given that PQR = SPR= 90˚, PQ = 8.5cm and PR = 12.3 cm. Calculate (a) QR (b) PS (c) The area of the trapezium PQRS.      Log On


   



Question 205868: PQRS is a trapezium where PQ // SR. Given that PQR = SPR= 90˚, PQ = 8.5cm and PR = 12.3 cm. Calculate (a) QR (b) PS (c) The area of the trapezium PQRS.
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
PQRS is a trapezium where PQ // SR. Given that PQR = SPR= 90˚, PQ = 8.5cm and PR = 12.3 cm. Calculate (a) QR (b) PS (c) The area of the trapezium PQRS.

You must be from the UK. In the US we say "trapezoid" and "math",
and you say "trapezium" and "maths".  :)



We can find QR by the Pythagorean theorem:

PQ%5E2%2BQR%5E2=PR%5E2

8.5%5E2%2BQR%5E2+=+12.3%5E2

72.25%2BQR%5E2=151.29

QR%5E2=79.04

QR=sqrt%2879.04%29

QR=8.890444308

Angles QPR and PRS are equal in measurement because they are alternate
interior angles formed by transversal PR intersecting two given parallel
line segments PQ and SR. And we are given that PQR = SPR = 90˚.  Therefore,
right triangles PQR and RPS are similar triangles.  Therefore their
sides are proportional, so we set up the proportion:




So:

PS%2FQR=PR%2FPQ 

PS%2F8.890444308=12.3%2F8.5

Solve that proportion equation and get  

PS+=+12.86499588

We find the areas of both triangles and add them.

To find the area of triangle PQR, we use formula

Area=base%2Aheight%2F2

Area=PQ%2AQR%2F2=8.5%2A8.890444308%2F2=37.78438831cm%5E2

To find the area of triangle RPS, we use formula

Area=base%2Aheight%2F2

Area=PS%2APR%2F2=12.86499588%2A12.3%2F2=79.11972467cm%5E2

Adding those areas together:

37.78438831cm%5E2%2B79.11972467cm%5E2=116.904113cm%5E2

Edwin