SOLUTION: hey,
could you please solve this problem for me, and thanks,
A rectangle, 3cm longer than it is wide, has a diagonal 15cm long. find the dimensions fo the rectangle.
i will
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-> SOLUTION: hey,
could you please solve this problem for me, and thanks,
A rectangle, 3cm longer than it is wide, has a diagonal 15cm long. find the dimensions fo the rectangle.
i will
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Question 160319: hey,
could you please solve this problem for me, and thanks,
A rectangle, 3cm longer than it is wide, has a diagonal 15cm long. find the dimensions fo the rectangle.
i will be waiting for the answer,
thank you again,
Draw the rectangle and its diagonal, putting
the length on the diagonal:
Label the width .
Since the length is 3 cm longer than the width,
label the length
Erase the upper left half of the rectangle:
That leaves a right triangle, with legs
and hypotenuse .
So we use the Pythagorean theorem:
with
Divide through by 2:
Think of two integers which
have product -108 and combine
to give +3:
They are -9 and +12, so the
left sides factors as:
Use the zero-factor principle
We choose the positive value for the width,
Therefore the width = 9cm
and the length = w+3 = 9+3 = 12cm
Edwin
You can put this solution on YOUR website! L=W+3
HERE YOU HAVE A RIGHT TRIANGLE OF SIDES L & W WITH AN HYPOTENUSE=15
THUS USING THE PYTHAGOREAN THEOREM (A^2+B^2=C^2)WE GET:
(W+3)^2+W^2=15^2
W^2+6W+9+W^2=225
2W^2+6W+9-225=0
2W^2+6W-216=0
2(W^2+3W-108)=0
2(W-9)(W+12)=0
W-9=0
W=9 FOR THE WIDTH
L=9+3=12 FOR THE LENGTH.
PROOF:
9^2+12^2=15^2
81+144=225
225=225