SOLUTION: Completely simplify and rationalize the denominator: (√160) / (√250) * (√245) / (√108)

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Question 1210715: Completely simplify and rationalize the denominator:
(√160) / (√250) * (√245) / (√108)

Answer by ikleyn(54057) About Me  (Show Source):
You can put this solution on YOUR website!
Completely simplify and rationalize the denominator:
(√160) / (√250) * (√245) / (√108)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~`

The starting number is 

    %28sqrt%28160%29%2Fsqrt%28250%29%29+%2A+%28sqrt%28245%29%2Fsqrt%28108%29%29.


To simplify writing, consider two factors separately,  sqrt%28160%29%2Fsqrt%28250%29  and  sqrt%28245%29%2Fsqrt%28108%29.


First factor  sqrt%28160%29%2Fsqrt%28250%29  is the same as  sqrt%28160%2F250%29.


In the last expression, reduce the common factor of 10 in the numerator and denominator under the square root, 
so you have

    sqrt%28160%29%2Fsqrt%28250%29 = sqrt%28160%2F250%29 = sqrt%2816%2F25%29 = 4%2F5.    (1)


Second factor  sqrt%28245%29%2Fsqrt%28108%29  is the same as  sqrt%28245%2F108%29.


In the last expression, transform

    sqrt%28245%29%2Fsqrt%28108%29 = sqrt%285%2A49%29%2Fsqrt%283%2A36%29 = %287%2F6%29%2Asqrt%285%2F3%29.    (2)


From (1) and (2), you have 

    %28sqrt%28160%29%2Fsqrt%28250%29%29+%2A+%28sqrt%28245%29%2Fsqrt%28108%29%29 = %284%2F5%29%2A%287%2F6%29%2Asqrt%285%2F3%29 = %2828%2F30%29%2Asqrt%285%2F3%29 = %2814%2F15%29%2A%28sqrt%285%29%2Fsqrt%283%29%29.    (3)


Now rationalize expression (3) multiplying it by  sqrt%283%29%2Fsqrt%283%29

    %2814%2F15%29%2A%28sqrt%285%29%2Fsqrt%283%29%29 = %2814%2F15%29%2A%28%28sqrt%285%29%2Asqrt%283%29%29%2F3%29 = %2814%2F15%29%2A%28sqrt%2815%29%2F3%29 = %2814%2Asqrt%2815%29%29%2F45.


At this point, the job is complete.


ANSWER.  %28sqrt%28160%29%2Fsqrt%28250%29%29+%2A+%28sqrt%28245%29%2Fsqrt%28108%29%29 = %2814%2Asqrt%2815%29%29%2F45.