SOLUTION: Simplify cube root of (2 + √5)

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Question 1206857: Simplify cube root of (2 + √5)
Found 3 solutions by MathLover1, ikleyn, Edwin McCravy:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

root%283%2C%282+%2B+sqrt%285%29%29%29...already simplest form
in decimal form it will be
1.61803399

Answer by ikleyn(52756) About Me  (Show Source):
You can put this solution on YOUR website!
.

See the solution under this link

https://www.youtube.com/watch?v=eWhAmW7IQt4



Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
We seek to find a simpler form root%283%2C2%2Bsqrt%285%29%29} 

We try to find a simpler expression of the same form as what's 
under the radical, namely a surd of the form a%2Bb%2Asqrt%285%29, where 
a and b are rational numbers.

If this is possible, then

root%283%2C2%2Bsqrt%285%29%29%22%22=%22%22a%2Bb%2Asqrt%285%29

Cubing both sides:

%28root%283%2C2%2Bsqrt%285%29%29%29%5E3%22%22=%22%22%28a%2Bb%2Asqrt%285%29%29%5E3

2%2Bsqrt%285%29%22%22=%22%22

2%2Bsqrt%285%29%22%22=%22%22a%5E3%2B3%2Aa%5E2%2Ab%2Asqrt%285%29%2B3%2Aa%2Ab%2A5%2Bb%5E3%285%2Asqrt%285%29%29

2%2Bsqrt%285%29%22%22=%22%22a%5E3%2B3%2Aa%5E2%2Ab%2Asqrt%285%29%2B15%2Aa%2Ab%5E2%2B5%2Ab%5E3%2Asqrt%285%29%29

The rational terms on the left must equal the rational terms on the right,
and The irrational terms on the left must equal the irrational terms on the
right, so we have this system

system%282=a%5E3%2B15ab%5E2%2C1=3a%5E2b%2B5b%5E3%29

Eliminate the constants by multiplying the 2nd equation by -2

system%282=a%5E3%2B15ab%5E2%2C-2=-6a%5E2b-10b%5E3%29

Adding the equations:

a%5E3-6a%5E2b%2B15ab%5E2-10b%5E3=0

Notice that the coefficients have sum 1-6+15-10 = 0.

That means a=b is a solution. Substituting a for b,

2=a%5E3%2B15ab%5E2

2=a%5E3%2B15a%5E3

2=16a%5E3

1=8a%5E3

1%2F8=a%5E3

Taking cube roots of both sides:

1%2F2=a

and since a=b, 

a%2Bb%2Asqrt%285%29

becomes

1%2F2%2Bexpr%281%2F2%29sqrt%285%29

Edwin