SOLUTION: Try to determine which column exerts greater partial pressure by putting
E on the blank if the column on the left is greater than the column on the right and
putting Z on the b
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E on the blank if the column on the left is greater than the column on the right and
putting Z on the b
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Question 1197129: Try to determine which column exerts greater partial pressure by putting
E on the blank if the column on the left is greater than the column on the right and
putting Z on the blank if the column on the right is greater than the column on the left.1.
Ptotal = 202 kPa
n1 = 0.4 mol
ntotal = 1.2 mol
or
Ptotal = 30 psi
n2 = 5 mol
ntotal = 14 mol
Ptotal = 0.83 atm
X1 = 0.23
or
Ptotal = 19 psi
X2 = 0.19 Found 2 solutions by onyulee, ikleyn:Answer by onyulee(41) (Show Source):
You can put this solution on YOUR website! **1. Calculate Partial Pressures**
* **Case 1:**
* Partial Pressure 1 (P1) = (n1 / ntotal) * Ptotal
* P1 = (0.4 mol / 1.2 mol) * 202 kPa = 67.33 kPa
* **Case 2:**
* Partial Pressure 2 (P2) = (n2 / ntotal) * Ptotal
* P2 = (5 mol / 14 mol) * 30 psi = 10.71 psi
* **Case 3:**
* Partial Pressure 3 (P3) = X1 * Ptotal
* P3 = 0.23 * 0.83 atm = 0.1909 atm
* **Case 4:**
* Partial Pressure 4 (P4) = X2 * Ptotal
* P4 = 0.19 * 19 psi = 3.61 psi
**2. Compare Partial Pressures**
* **Case 1 vs. Case 2:**
* **Case 1 has a higher partial pressure.** (kPa is a larger unit than psi)
* **Answer: E**
* **Case 3 vs. Case 4:**
* **Case 3 has a higher partial pressure.** (0.1909 atm > 3.61 psi)
* **Answer: E**
**Therefore, the answers are:**
* **E**
* **E**