SOLUTION: A cone-shaped paper drinking cup is to hold 40cm^3 of water. Find the height and radius of the cup that will require the least amount of paper. NOTE: Enter the exact answers.

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Question 1196998: A cone-shaped paper drinking cup is to hold 40cm^3 of water. Find the height and radius of the cup that will require the least amount of paper. NOTE: Enter the exact answers.
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi  
A cone-shaped paper drinking cup is to hold  40cm^3 of water. 
Find the height and radius of the cup that will require the least amount of paper.
NOTE: Enter the exact answers. 

V= 1/3 πr^2h = 40cm^3 0r +h+=+120%2F%28pi%2Ar%5E2%29
As my distinguished colleague pointed out... 
following REPRESENTS surface area of the 'cup'.
S = +pi%2Ar%2Asqrt%28r%5E2+%2B+%28120%2F%28pi%2Ar%5E2%29%29%5E2%29
Using graphing calculator: S' = ~0(.00003)  at r = ~3.0035cm
 r = ~3.0035  then h = +h+=+120%2F%28pi%2A3.0035%5E2%29 =4.2342
checking:
V= 1/3 πr^2h = 40cm^3
V= 1/3 π(3.0035^2)4.2342 = 39.9996 
AS Instructed:  "NOTE: Enter the 'exact answers. " 
Yes, one would need to use set S' = 0 & solve for r in terms of pi
That having been said:
The Graphing Calculator is a 'great way' to find answer to 4 decimal points.
Wish You the Best in your Studies.


Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.
A cone-shaped paper drinking cup is to hold 40cm^3 of water.
Find the height and radius of the cup that will require
the least amount of paper. NOTE: Enter the exact answers.
~~~~~~~~~~~~~~~~


            The  "solution"  by  @ewatrrr is  INCORRECT.

            It is incorrect,  since she uses the formula for the total surface area of the cone,
            including its base,  while in this problem the area of the base of the cone should  NOT  be included
            and should not be considered,  at all.

            So,  I came to bring a correct solution.


The volume of the cone cup is given 40 cm^3.


The lateral area of a cone is

    S = pi%2Ar%2As,       (1)

where r is the base radius and "s" is the slant height:  s = sqrt%28h%5E2+%2B+r%5E2%29.

So, we need minimize the lateral area

    S = pi%2Ar%2Asqrt%28h%5E2%2Br%5E2%29    (2)


at given restriction for the volume

    %281%2F3%29%2Api%2Ar%5E2%2Ah = 40  cm^3.    (3)


From the restriction (3),   

    h = 120%2F%28pi%2Ar%5E2%29. 


We substitute it into expression (2), and we get S(r) as a function of the radius r, only

    S(r) = pi%2Ar%2Asqrt%28%2814400%2F%28pi%5E2%2Ar%5E4%29%29+%2B+r%5E2%29 = sqrt%28%2814400%2Fr%5E2%29+%2B+pi%5E2%2Ar%5E4%29


    +-------------------------------------------------------+
    |    To find the minimum of S(r), we should calculate   |
    |         the derivative and equate it to zero.         |
    +-------------------------------------------------------+


I will not calculate the derivative in full, which is a complicated fraction. 
It is enough to calculate its numerator and equate it to zero. It gives this equation

    -2%2A%2814400%2Fr%5E3%29 + 4%2Api%5E2r%5E3 = 0,

or, equivalently

    7200 = pi%5E2%2Ar%5E6,   r%5E6 = 7200%2Fpi%5E2,   r = root%286%2C7200%2Fpi%5E2%29 = 3.0 cm.    (4)


So, the radius is just found.  The height should be  

    h = 120%2F%28pi%2Ar%5E2%29 = 120%2F%28pi%2A3%5E2%29 = 4.24 cm.    (5)


Expressions (4) and (5) give the required exact formulas and approximate numerical values.

Solved.

-------------------

For your safety,  ignore the post by @ewatrrr,  since her solution is incorrect.

From day to day,  this woman repeats the same error:  she tries to solve problems that are out of her competency.