SOLUTION: There were 12 girls and 3 boys in a group of children. One child was chosen at random from the group. Another child was chosen at random from the remaining children. Expressing ea

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Question 1196515: There were 12 girls and 3 boys in a group of children. One child was chosen at random from the group. Another child was chosen at random from the remaining children.
Expressing each answer as a fraction in its simplest form, calculate the probability that
(a) the first child chosen was a girl,
(b) the first chosen was a girl and the second was a boy,
(c) a child of each sex was chosen.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi  

Group of 15:  12 girls, 3 boys
One child was chosen at random from the group. 
Another child was chosen at random from the remaining children.
Calculate the probability(express as fraction in simplest form):

(a) the first child chosen was a girl.  12%2F15+=+green%284%2F5%29
(b) the first chosen was a girl AND the second was a boy.  %2812%2F15%29%283%2F14%29+=+green%286%2F35%29
(c) a child of each sex was chosen. (b) OR  boy first & girl second
green%286%2F35%29  + %283%2F15%29%2812%2F14%29 = 6%2F35+%2B+6%2F35+=+green%2812%2F35%29
Wish You the Best in your Studies.