Question 1195554: Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms into another atom (polonium-210 in this case) each day. If you begin with 133 mg of Bismuth-210, how much remains after 6 days?
After 6 days,
mg of Bismouth-210 remains.
Answer by ikleyn(52775)   (Show Source):
You can put this solution on YOUR website! .
Bismuth-210 is an isotope that radioactively decays by about 13% each day,
meaning 13% of the remaining Bismuth-210 transforms into another atom
(polonium-210 in this case) each day. If you begin with 133 mg of Bismuth-210,
how much remains after 6 days?
After 6 days,
mg of Bismouth-210 remains.
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The remaining mass of Bismuth-210 after one day is
M(1) =  =  ,
where M(0) is the starting amount of Bismuth-210.
After 2 days the remainig mass is  .
After 3 days the remainig mass is  .
. . . and so on . . .
After n days the remainig mass is M(n) =  .
Concretely for this problem, the remaining mass after 6 days will be
M(6) =  = 57.672 mg (rounded). ANSWER
Solved.
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On radioactive decay, see the lesson
- Radioactive decay problems
in this site.
You will find many similar (and different) solved problems there.
Use this lesson as your handbook, textbook, guide, tutorials, and (free of charge) home teacher.
Learn the subject from there once and for all.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Logarithms".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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