SOLUTION: Evaluate the following Inverse Trigonometric Function. a. 𝑠𝑖𝑛^−1 (−1) b. 𝑡𝑎𝑛^−1 (−1)

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Question 1195258: Evaluate the following Inverse Trigonometric Function.
a. 𝑠𝑖𝑛^−1 (−1)
b. 𝑡𝑎𝑛^−1 (−1)
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.

(a) sin%5E%28-1%29+%28-1%29 = -+pi%2F2     ( since  sin%28-+pi%2F2%29 = -1 ).


(b) tan%5E%28-1%29+%28-1%29 = -+pi%2F4     ( since  tan%28-+pi%2F4%29 = -1 ).

Solved.


In this post,  I treat  sin%5E%28-1%29+%28x%29  as  arcsin(x)  and treat  tan%5E%28-1%29+%28x%29  as  arctan(x).