SOLUTION: In a professional division of a Hockey league, there are 9 total teams. How many different rankings are possible at the end of the year? (Hint: there are no ties.) Select one:

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Question 1194622: In a professional division of a Hockey league, there are 9 total teams. How many different rankings are possible at the end of the year? (Hint: there are no ties.)
Select one:
a.
40,320

b.
362,880

c.
3,628,750

d.
181,440
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

In this problem,  each ranking is a list of teams,  ordered according to their ranks.

In other words,  each ranking is some ordered list,  or a permutation of  9  teams.

For 9 items/(teams),  there are   9! = 9*8*7*6*5*4*3*2*1 = 362880  possible permutations/(rankings).     ANSWER


        Solved and explained.


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It is about  PERMUTATIONS.


On  Permutations,  see introductory lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Simple and simplest problems on permutations
    - Special type permutations problems
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.