SOLUTION: An arrow is shot upward with an initial velocity of 80 feet per second. The height of the arrow, h(t), in terms of the time since the arrow was released t, is h(t)= 80t - 16t². Ho
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-> SOLUTION: An arrow is shot upward with an initial velocity of 80 feet per second. The height of the arrow, h(t), in terms of the time since the arrow was released t, is h(t)= 80t - 16t². Ho
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Question 1188664: An arrow is shot upward with an initial velocity of 80 feet per second. The height of the arrow, h(t), in terms of the time since the arrow was released t, is h(t)= 80t - 16t². How long after the arrow is released does it reach its maximum height? What is the maximum height?''. Answer by Shin123(626) (Show Source):
