SOLUTION: The coefficient of x^2 is 69 in the expansion of (1-ax)^24, where a > 0. Find the coefficient of x^3.
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Question 1187157
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The coefficient of x^2 is 69 in the expansion of (1-ax)^24, where a > 0. Find the coefficient of x^3.
Answer by
greenestamps(13198)
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In the expansion of
, the coefficient of the x^2 term is
Given that that coefficient is 69, we have
OR
So there are going to be two different possible answers for the coefficient of x^3.
ANSWER #1:
ANSWER #2: