SOLUTION: Find the values of a if coefficient of x^2 in expansion (2+16x)/(2+ax)^3 is -9/2.

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Question 1171441: Find the values of a if coefficient of x^2 in expansion (2+16x)/(2+ax)^3 is -9/2.
Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


There is no x^2 term in the expansion....

The numerator has terms of degree 1 and 0; the denominator when expanded will have terms of degree 3, 2, 1, and 0.

The terms in the expanded expression will have degrees with a maximum of 1-0=1 and a minimum of 0-3=-3.