SOLUTION: At what point(s) on the curve f (x) = 2 - 4x^3 does the function have a perpendicular slope of 3?

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Question 1163296: At what point(s) on the curve f (x) = 2 - 4x^3 does the function have a perpendicular slope of 3?
Found 2 solutions by ikleyn, solver91311:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.

This problem, word-in-word, was posted yesterday to this forum,

and one of the tutors REACTED on it saying that this formulation DOES NOT MAKES SENSE.

I confirm, that this formulation DOES NOT MAKE SENSE.

Do not post it in this form again.


And have a nice day (!)



Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I suspect you mean at which points on the graph of does the graph have a normal with a slope equal to 3?

A normal to a curve is perpendicular to a tangent to the curve. Perpendicular lines have negative reciprocal slopes. So take the first derivative of your function and set that function equal to . Since you are dealing with a cubic polynomial, one would expect the derivative to be a quadratic with two zeros.


John

My calculator said it, I believe it, that settles it