SOLUTION: Consider the parabola y=x2−6x+4.
What is the axis of symmetry? x=
Compute the coordinates of the vertex: (
,
)
compute the y-intercept as a point: (
,
)
find the po
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-> SOLUTION: Consider the parabola y=x2−6x+4.
What is the axis of symmetry? x=
Compute the coordinates of the vertex: (
,
)
compute the y-intercept as a point: (
,
)
find the po
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Question 1159743: Consider the parabola y=x2−6x+4.
What is the axis of symmetry? x=
Compute the coordinates of the vertex: (
,
)
compute the y-intercept as a point: (
,
)
find the point symmetric to the y-intercept: Found 2 solutions by MathLover1, MathTherapy:Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website! Consider the parabola
What is the axis of symmetry?
The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.
so, write your equation in vertex form: ....complete square
...... -> and , so x -coordinate of the vertex is
Compute the coordinates of the vertex: done above
(,)
compute the y-intercept as a point:
y-intercept where
(,)
find the point symmetric to the y-intercept
axis of symmetry is , so axis is three units to the right from the y-intercept, and the point symmetric to the y-intercept will be three more units to the right from axis at:
(,)
You can put this solution on YOUR website!
Consider the parabola y=x2−6x+4.
What is the axis of symmetry? x=
Compute the coordinates of the vertex: (
,
)
compute the y-intercept as a point: (
,
)
find the point symmetric to the y-intercept:
Axis of symmetry:
y-coordinate of vertex:
Coordinates of the vertex:
Substitute 0 for x in the equation, and compute to get the y-intercept!
