SOLUTION: Set-Builder Notation and Interval Notation. Suppose A={x is an element of real number: -2 less than or equal to X < 5 } and B= (-1, 6] 1. Find A U B and give the answer in interv

Algebra ->  Test -> SOLUTION: Set-Builder Notation and Interval Notation. Suppose A={x is an element of real number: -2 less than or equal to X < 5 } and B= (-1, 6] 1. Find A U B and give the answer in interv      Log On


   



Question 1158642: Set-Builder Notation and Interval Notation.
Suppose A={x is an element of real number: -2 less than or equal to X < 5 } and B= (-1, 6]
1. Find A U B and give the answer in interval notation. (7marks)
2. Write A n (intersection) B as one set using set builder notation (4marks)

Answer by MathLover1(20849) About Me  (Show Source):
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Set-Builder Notation and Interval Notation.
Suppose A={ x is an element of real number: -2+%3C=x+%3C+5 } and B= (-1, 6]
=>A=-2,-1,0,1,2,3,4
=>B=-2,-1,0,1,2,3,4,5,6

1. Find A U B and give the answer in interval notation.
means: the new set that contains every element from either of A and +B
in your case B contains every element from A and some more, so union is actually set B
A U B=B=-2,-1,0,1,2,3,4,5,6
in interval notation: (-1, 6]

2. Write A (intersection) B as one set using set builder notation.
means: the new set that contains every element that is in both of the input sets; only things inside both of the input sets get added to the new set
in your case all elements of A are also elements of B, so intersection is actually set A
+AB= A=-2,-1,0,1,2,3,4

{ x is an element of real number: -2+%3C=x+%3C+5 }