Question 1158623: Determine the location and value of the absolute extreme values of f on the given interval, if they exist.
f(x) =4sqrt(x) −8x^2/x
on [1,10]
Answer by KMST(5396) (Show Source):
You can put this solution on YOUR website! The function f(x)=4sqrt(x)−8x^2/x is not a very interesting one, and may not the the function intended.
I suspect the function intended could have been f(x)=(4sqrt(x)-8x^2)/x , which means   , also not an interesting function.
The domain of f(x)=(4sqrt(x)-8x^2)/x is , which can be expressed as   .
The graph of    is 
The derivative is negative throughout the domain of the function, meaning that the function decreases continuously.
Its absolute extremes in the interval [1, 10] are
        , a maximum, and
    , a minimum, with a rounded value of 
The domain of f(x)=4sqrt(x)−8x^2/x is   .
That function is    
Its graph is 
The derivative is negative throughout the domain of the function, meaning that the function decreases continuously.
Its absolute extremes in the interval [1, 10] are
, a maximum, and
, a minimum, with a rounded value of
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