SOLUTION: Determine whether Rolle's theorem applies to the function shown below on the given interval. If so, find the point(s) that are guaranteed to exist by Rolle's theorem. f(x)=x(x-8)^

Algebra ->  Test -> SOLUTION: Determine whether Rolle's theorem applies to the function shown below on the given interval. If so, find the point(s) that are guaranteed to exist by Rolle's theorem. f(x)=x(x-8)^      Log On


   



Question 1155428: Determine whether Rolle's theorem applies to the function shown below on the given interval. If so, find the point(s) that are guaranteed to exist by Rolle's theorem.
f(x)=x(x-8)^2; [0,8]

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Rolle's Theorem
Let f be differentiable on the open interval (a,b) and continuous on the closed interval [a,b].
Then if f%28a%29=f%28b%29, then there is at+least one point c in (a,b) where f'%28c%29=0.


f%28x%29=x%28x-8%29%5E2;
[0,8]=[a,b]
check if f%28a%29=f%28b%29 for
a=0
b=8
f%280%29=0%280-8%29%5E2=0
f%288%29=8%288-8%29%5E2=0
=> f%28a%29=f%28b%29
then derivate
f%28x%29=x%28x-8%29%5E2
apply the Product Rule : %28f%2Ag+%29'=f'*g+f* g'
f'%28x%29=%28d%2Fdx%29x%2A%28x-8%29%5E2%2Bx%2A%28d%2Fdx%29%28x-8%29%5E2
f'%28x%29=1%2A%28x-8%29%5E2%2Bx%2A2%28x-8%29
f'%28x%29=x%5E2-16x%2B64%2B2x%5E2-16x
f'%28x%29+=+3+x%5E2+-+32+x+%2B+64
find point c in (a,b) where f'%28c%29=0
+3x%5E2+-+32x+%2B+64=0
3x%5E2+-+24x-8x+%2B+64=0
%283+x%5E2+-+24x%29-%288x+-+64%29=0
%28x+-+8%29+%283x+-+8%29+=+0
solutions:
if %28x+-+8%29+=+0=>x=8
if +%283x+-+8%29+=+0=>x=8%2F3
the point(s) that are guaranteed to exist by Rolle's theorem are:
(8,0) and (8%2F3,0)