Question 1155422: Find the critical points of the following function.
f(x)=2x^2-3x-5
Found 2 solutions by MathLover1, MathTherapy: Answer by MathLover1(20849) (Show Source): Answer by MathTherapy(10552) (Show Source):
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Find the critical points of the following function.
f(x)=2x^2-3x-5
There are 3 CRITICAL points of a parabola. They are:
1) the y-intercept (it's obvious that this is - 5)
2) the x-intercepts, if any [solving the equation for x, by setting f(x) = 0 will accomplish this task, and also, this equation can be FACTORED]
3) the VERTEX (this is found by determining the x-coordinate of the vertex, using the formula: , and then substituting this x-value into f(x)
to get the y-coordinate of the vertex. These 2 coordinates will give you the vertex of the parabola, which by the way is a MINIMUM, as indicated by the
leading coefficient being > 0. Alternatively, you can convert the function to the vertex form of a parabola, but that may be too much work!
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