SOLUTION: find the value of y if the mean of 22, 18, (2y+1) 10 and 20 is 25

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Question 1150896: find the value of y if the mean of 22, 18, (2y+1) 10 and 20 is 25
Found 2 solutions by ankor@dixie-net.com, ikleyn:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
find the value of y if the mean of 22, 18, (2y+1) 10 and 20 is 25
%28%2822%2B18%2B%282y%2B1%29%2B10%2B20%29%29%2F6 = 25
Multiply both sides by 6
22+18+(2y+1)+10+20 = 6*25
2y + 71 = 150
2y = 150 - 71
2y = 79
y = 79/2
y = 39.5
:
:
check
2y+1: 2(39.5) + 1 = 80
%28%2822%2B18%2B80%2B10%2B20%29%29%2F6 =
150/6 = 25

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

In your post,  it should be  EITHER  comma between  (2y+1)  and  10,  OR  the multiplication sign.

But not the  "blank space",  which violates the logic of your post and makes the problem/(the post)  non-sensical.


Also, do not consider the  "solution"  by @ankor@dixie-net.com  seriously,
since in his first line formula he uses  INCORRECT  total number of terms in the sequence.