SOLUTION: What are possible values of x for the following functions? A) x=3x÷([x-1]×[x-2]) B) x=(2-x)÷(x×[x-1]) C) x=(x-3)÷(2x+6) D) x=(x+5)÷(10-2x) Thank you so much! :) Thanks

Algebra ->  Test -> SOLUTION: What are possible values of x for the following functions? A) x=3x÷([x-1]×[x-2]) B) x=(2-x)÷(x×[x-1]) C) x=(x-3)÷(2x+6) D) x=(x+5)÷(10-2x) Thank you so much! :) Thanks       Log On


   

Question 1144448: What are possible values of x for the following functions?
A) x=3x÷([x-1]×[x-2])
B) x=(2-x)÷(x×[x-1])
C) x=(x-3)÷(2x+6)
D) x=(x+5)÷(10-2x)
Thank you so much! :)
Thanks again.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
#A:
The algebraic steps should lead to x%28x%5E2-3x-1%29=0.

The factor, x, means one solution is x=0.

The quadratic factor will mean that two more solutions are x=%283%2B-+sqrt%2813%29%29%2F2.


#B:
A start,
x-%282-x%29%2F%28x%28x-1%29%29=0
.
.
x%5E3-x%5E2%2Bx-2=0

Try Rational Roots Theorem to try to find any rational roots; but understand, x at 0 is not a solution and x at 1 is not a solution; because each will fail in the original equation.