SOLUTION: Let a,b,c be real numbers satisfy ab + bc + ca = 1. Show that (a - b)/(1 + c^2) + (b - c)/(1 + a^2) ≥ (c - a)/(1 + b^2)

Algebra ->  Test -> SOLUTION: Let a,b,c be real numbers satisfy ab + bc + ca = 1. Show that (a - b)/(1 + c^2) + (b - c)/(1 + a^2) ≥ (c - a)/(1 + b^2)      Log On


   



Question 1135967: Let a,b,c be real numbers satisfy ab + bc + ca = 1. Show that (a - b)/(1 + c^2) + (b - c)/(1 + a^2) ≥ (c - a)/(1 + b^2)
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Let a,b,c be real numbers satisfy ab + bc + ca = 1. Show that (a - b)/(1 + c^2) + (b - c)/(1 + a^2) ≥ (c - a)/(1 + b^2)
Let's see if it's true when a=-2, b=3, and c=7

ab+%2B+bc+%2B+ca+=+1. 

%28-2%29%283%29+%2B+%283%29%287%29+%2B+%287%29%28-2%29+=+-6%2B21-14+=+1 

That checks.  Now let's see if this checks:





%28-5%29%2F%281+%2B+49%29+%2B+%28-4%29%2F%281+%2B+4%29+%3E=+%287%2B2%29%2F%281+%2B+9%29

%28-5%29%2F%2850%29+%2B+%28-4%29%2F%285%29+%3E=+%2811%29%2F%2810%29

-1%2F10-4%2F5+%3E=+11%2F10

-1%2F10-8%2F10+%3E=+11%2F10

-9%2F10+%3E=+11%2F10

FALSE.  So the proposition is FALSE.  Sorry.

Edwin