SOLUTION: A shot putter throws the shot with an initial speed of 14 m/s at a 40 degrees angle to the horizontal. Calculate the horizontal distance traveled by the shot?
Algebra ->
Test
-> SOLUTION: A shot putter throws the shot with an initial speed of 14 m/s at a 40 degrees angle to the horizontal. Calculate the horizontal distance traveled by the shot?
Log On
Question 1129537: A shot putter throws the shot with an initial speed of 14 m/s at a 40 degrees angle to the horizontal. Calculate the horizontal distance traveled by the shot? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A shot putter throws the shot with an initial speed of 14 m/s at a 40 degrees angle to the horizontal. Calculate the horizontal distance traveled by the shot?
-----------
The vertical speed at launch is 14*sin(40) m/sec =~ 8.999 m/sec
Using 9.8 m/sec/sec for Earth's gravity:
h(t) = -4.9t^2 + vo*t + h where vo is the launch speed (8.999) and h is the launch (which was not given)
-----------
h(t) = -4.9t^2 + 8.999t =0 at impact
Solve for t (Ignore t = 0)
====================
The horizontal speed is 14*cos(40) =~ 10.725 m/sec
Horizontal distance = 10.725t
---------
The height at launch should be taken into account.
