SOLUTION: reduce in echelon form or rref <pre> x_1 - x_2 - 2x_3 + x_4 + 11x_5 = 13 x_1 - x_2 + x_3 + x_4 + 5x_5 = 16 2x_1 - 2x_2 + 0x_3 + x_4 + 10x_5 = 21 2x_1 - 2x_2

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Question 1122274: reduce in echelon form or rref

x_1 - x_2 - 2x_3 + x_4 + 11x_5 = 13 x_1 - x_2 + x_3 + x_4 + 5x_5 = 16 2x_1 - 2x_2 + 0x_3 + x_4 + 10x_5 = 21 2x_1 - 2x_2 - x_3 + 3x_4 + 20x_5 = 38 2x_1 - 2x_2 + x_3 + x_4 + 8x_5 = 22

Found 2 solutions by solver91311, Alan3354:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

There is a myriad of Gauss-Jordan Row Reduction Calculators out there. This one gives a good detailed step by step solution.

Reshish Gauss-Jordan Elimination Calculator

John

My calculator said it, I believe it, that settles it

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
This is very tedious and error prone.
It's important that you know how to do it, but not that you get the "right answer."
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I don't need the practice.
you try it, email via the TY note for help if needed.

SOLUTION: reduce in echelon form or rref <pre> x_1 - x_2 - 2x_3 + x_4 + 11x_5 = 13 x_1 - x_2 + x_3 + x_4 + 5x_5 = 16 2x_1 - 2x_2 + 0x_3 + x_4 + 10x_5 = 21 2x_1 - 2x_2 - x_3 +