SOLUTION: At noon a culture of bacteria had 2.5x10^6 members, and at 3 pm the population was 4.5x10^6. Assuming exponential growth, find when the population will be 8.0x10^6.

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Question 1122273: At noon a culture of bacteria had 2.5x10^6 members, and at 3 pm the population was 4.5x10^6. Assuming exponential growth, find when the population will be 8.0x10^6.
Found 2 solutions by josgarithmetic, Theo:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Assume the population quantities is in millions.
Noon, 2.5 million, time 0

3 pm, time 3; population 4.5

2.5%2Ab%5E3=4.5

b%5E3=4.5%2F2.5

b%5E3=1.8

b=1.2164, approximate cube root of 1.8

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2.5%2A%281.2164%29%5Ex=8
Solve for x.

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
you first need to find the exponential growth rate.

the formula for that is f = p * e^(rt)

f is equal to 4.5 * 10^6
p is equal to 1.5 * 10^6
t is equal to 3

you are solving for r.

formula becomes 4.5 * 10^6 = 1.5 * 10^6 * e^(3r)

divide both sides of this formula by 1.5 * 10^6 to get:

4.5 * 10^6 / (1.5 * 10^6) = e^(3r)

take the natural log of both sides of this formula and simplify to get:

ln(3) = ln(e^3r)

since ln(e^3r) is equal to 3r * ln(e) and ln(e) is equal to 1, this equation becomes:

ln(3) = 3r

solve for r to get:

r = ln(3) / 3

this results in r = .3662040962

that's your hourly exponential growth rate.

to see if this is good, take 1.5 * 10^6 and multiply it by e^(.3662040962 * 3).

you will get 4.5 * 10^6 which is exactly what you want, assuming the rate is calculated correctly, as it is.

to find out when the population will reach 8.0 * 10^6, use the same formula of f = p * e^(rt).

if you are starting from 1.5 * 10^6, the formula becomes:

8.0 * 10^6 = 1.5 * 10^6 * e^(.3662040962 * t)

divide both sides of the equation by 1.5 * 10^6 to get:

8.0 * 10^6 / (1.5 * 10^6) = e^(.3662040962 * t)

take the natural log of both sides and simplify to get:

ln(5 + 1/3) = .3662040962 * t

solve for t to get:

t = ln(5 + 1/3) / .3662040962 = 4.571157043

to confirm, take 1.5 * 10^6 and multiply it by e^(.3662040962 * 4.571157043).

you will get 8.0 * 10^6, as you should.

if you had started from 4.5 * 10^6, the formula would have become:

8.0 * 10^6 = 4.5 * 10^6 * e^(.3662040962 * t)

in that case, you would have solved for t to get:

t = ln(8.0 * 10^6 / (4.5 * 10^6) / .3662040962, resulting in:

t = 1.571157043

add that to the 3 hours to get from 1.5 * 10^6 to 4.5 * 10^6 and the total hours is 4.571157043.

the total hours to get from 1.5 to 4.5 million = 3.

the total hours to get from 4.5 to 8 million = 1.571157043

the total hours to get from 1.5 to 8 million = 4.571157043

the formula for this problem can be graphed as shown below:

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