SOLUTION: Let f(x)=x+1 and define s(x) to be the slope of the line through the points (0,0) and (x,f(x)). a. Evaluate: s(5) and s(-2); b. Find an equation for s(x) in terms of x. Note th

Algebra ->  Test -> SOLUTION: Let f(x)=x+1 and define s(x) to be the slope of the line through the points (0,0) and (x,f(x)). a. Evaluate: s(5) and s(-2); b. Find an equation for s(x) in terms of x. Note th      Log On


   



Question 1120800: Let f(x)=x+1 and define s(x) to be the slope of the line through the points (0,0) and (x,f(x)). a. Evaluate: s(5) and s(-2); b. Find an equation for s(x) in terms of x.
Note that fractional answers must be expressed like -5/6, and answers with exponents like (x^2-1)/(x+3). Use lower case letters.and do not use spaces in your answers.
Answer would be:
a. s(5) = ___ and s(2) = ___
b. s(x) = ___

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!


if s%28x%29 is the slope of the line through the points (0,0) and (x,f%28x%29), we have:
s%28x%29=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 ....use given points (0,0) and (x,f%28x%29) or (0,0) and (x,x%2B1)
s%28x%29=%28x%2B1-0%29%2F%28x-0%29
s%28x%29=%28x%2B1%29%2Fx
s%28x%29=x%2Fx%2B1%2Fx
s%28x%29=1%2B1%2Fx+ -> answer to b. an equation for s%28x%29 in terms of x

a. Evaluate: s%285%29 and s%28-2%29;
s%285%29+=1%2B1%2F5=5%2F5%2B1%2F5=6%2F5
s%285%29+=1%2B1%2F-2=1-1%2F2=1%2F2