SOLUTION: A ship leaves port at 6am travelling due east at 12mph. Another ship leaves port at 11 am travelling due north at 15mph. How far apart, to the nearest tenth of a mile, are the two
Algebra ->
Test
-> SOLUTION: A ship leaves port at 6am travelling due east at 12mph. Another ship leaves port at 11 am travelling due north at 15mph. How far apart, to the nearest tenth of a mile, are the two
Log On
Question 1088656: A ship leaves port at 6am travelling due east at 12mph. Another ship leaves port at 11 am travelling due north at 15mph. How far apart, to the nearest tenth of a mile, are the two ships at 11pm? Answer by natolino_2017(77) (Show Source):
You can put this solution on YOUR website! First, let's see the distance travelled for the first ship
Distance1 = 12 Mile/hr*17 hours = 204 Miles.
Second distance is the one travelled of the second ship
Distance2 = 15 Mile/hr*12 hours =180 Miles.
as the first ship travelled to the east and the second ship travels to the north, the 204 miles and 180 miles are the legs of a rectangle triangle.
The distance is the hypotenuse of the triangle:
= 272.1 Miles
@natolino_
(