SOLUTION: what is the equation of this line?
question: find the equations of the line described.
tangent lines to x²+y²-18x-2y+48=0 at points where x=4
im solving it using x²+y²-18y
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-> SOLUTION: what is the equation of this line?
question: find the equations of the line described.
tangent lines to x²+y²-18x-2y+48=0 at points where x=4
im solving it using x²+y²-18y
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Question 1085762: what is the equation of this line?
question: find the equations of the line described.
tangent lines to x²+y²-18x-2y+48=0 at points where x=4
im solving it using x²+y²-18y-2y+48=0
at x=4
my solution (trying)
P(4,y)
(4)²+y²-18(4)-2y+48=0
16+y²-72-2y+48=0
=y²+2y
=y(y+2)=0
y=0 | y+2=0 y=-2
is it right?
P(4,0) Q(4,-2) is it right?
x²+y²-18x-2y+48=0
(x²-18x)+(y²-2y)= -48
is it right? now i dont know whats next. please correct me if im wrong.
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