SOLUTION: the altitude of a triangle is increasing at a rate of 1 cm/min
while the area of the triangle is increasing at a rate of 2cm^2/min.
At what rate is the base of the triangle cha
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-> SOLUTION: the altitude of a triangle is increasing at a rate of 1 cm/min
while the area of the triangle is increasing at a rate of 2cm^2/min.
At what rate is the base of the triangle cha
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Question 1084628: the altitude of a triangle is increasing at a rate of 1 cm/min
while the area of the triangle is increasing at a rate of 2cm^2/min.
At what rate is the base of the triangle changing when the altitude
is 10cm and the area is 100cm^2? Answer by Edwin McCravy(20054) (Show Source):
>>the altitude (height h) of a triangle is increasing
at a rate of 1 cm/min<<
>>while the area A of the triangle is increasing at a
rate of 2cm^2 /min.<<
>>at what rate is the base of the triangle changing...<<
Substitute and
Multiply both side by 2
We will need b and h to solve for .
>>when the altitude (height h) is 10cm and the area is 100cm^2?<<
We go back to the area formula:
Substitute and in
The negative sign means the base is DEcreasing
at the rate of -1.6 cm/min at that instant.
Edwin
