SOLUTION: If given, {{{ x = t+3 }}} & {{{ y = t^2 - 3t }}}, eliminate the parameter A.) {{{ y = x^2+9x + 9 }}} B.) {{{ y = x^2+9x + 18 }}} C.) {{{ y = x^2-6x + 9 }}} D.) {{{ y = x^2-9x

Algebra ->  Test -> SOLUTION: If given, {{{ x = t+3 }}} & {{{ y = t^2 - 3t }}}, eliminate the parameter A.) {{{ y = x^2+9x + 9 }}} B.) {{{ y = x^2+9x + 18 }}} C.) {{{ y = x^2-6x + 9 }}} D.) {{{ y = x^2-9x      Log On


   

Question 1079502: If given, +x+=+t%2B3+ & +y+=+t%5E2+-+3t+, eliminate the parameter
A.) +y+=+x%5E2%2B9x+%2B+9+
B.) +y+=+x%5E2%2B9x+%2B+18+
C.) +y+=+x%5E2-6x+%2B+9+
D.) +y+=+x%5E2-9x+%2B+18+
Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
Express "t" from the first equation

t = x-3

and substitute it into the second equation y = t^2 -3t. You will get

y = %28x-3%29%5E2+-+3%28x-3%29.

Simplify further, and you will get

y = x%5E2+-+6x+%2B+9+-+3x+%2B+9 = x%5E2-9x+%2B+18.


Thus the answer is option D).