SOLUTION: Find the equation of a Parabola with Vertex: (2,-1) and directrix: x= -2
(y-1)² = 16(x-2)
(y-1) = 16(x+2)²
(y+1) = 16(x-2)²
(y+1)² = 16(x-2)
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-> SOLUTION: Find the equation of a Parabola with Vertex: (2,-1) and directrix: x= -2
(y-1)² = 16(x-2)
(y-1) = 16(x+2)²
(y+1) = 16(x-2)²
(y+1)² = 16(x-2)
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Question 1078986: Find the equation of a Parabola with Vertex: (2,-1) and directrix: x= -2
(y-1)² = 16(x-2)
(y-1) = 16(x+2)²
(y+1) = 16(x-2)²
(y+1)² = 16(x-2) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The vertex would give a (y+1), (x-2) picture, and the directrix at x=-2 would mean a parabola opening horizontally, so the y would be squared, not the x.
(y+1)^2-16(x-2).
