SOLUTION: The standard form equation of a circle with center at (-4,2) and radius 4 is A.) (x-4)² + (y+2)² = 16 B.) (x-4)² + (y+2)² = 4 C.) (x+4)² + (y-2)² = 16 D.) (x+4)² + (y-2)² = 4

Algebra ->  Test -> SOLUTION: The standard form equation of a circle with center at (-4,2) and radius 4 is A.) (x-4)² + (y+2)² = 16 B.) (x-4)² + (y+2)² = 4 C.) (x+4)² + (y-2)² = 16 D.) (x+4)² + (y-2)² = 4      Log On


   

Question 1078984: The standard form equation of a circle with center at (-4,2) and radius 4 is
A.) (x-4)² + (y+2)² = 16
B.) (x-4)² + (y+2)² = 4
C.) (x+4)² + (y-2)² = 16
D.) (x+4)² + (y-2)² = 4
Found 2 solutions by josgarithmetic, Boreal:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
C. This will be (x+4)^2+(y-2)^2=16
reverse the signs of the coordinates and put by the x and y, square the radius.