SOLUTION: find (a)2v + u, (b)u -3v, and (c)5u - v in the equation of 11. u = <-2, -3>, v = <-1,-10> Have, u=(-2,3) v=(-1,-10) 2v+u=(-2,-20)+(-1,-10) 2v+u=(-2+(-1),-20+(-10)) 2v+u=(

Algebra ->  Test -> SOLUTION: find (a)2v + u, (b)u -3v, and (c)5u - v in the equation of 11. u = <-2, -3>, v = <-1,-10> Have, u=(-2,3) v=(-1,-10) 2v+u=(-2,-20)+(-1,-10) 2v+u=(-2+(-1),-20+(-10)) 2v+u=(      Log On


   



Question 1077545: find (a)2v + u, (b)u -3v, and (c)5u - v in the equation of 11. u = <-2, -3>, v = <-1,-10>
Have,
u=(-2,3)
v=(-1,-10)
2v+u=(-2,-20)+(-1,-10)
2v+u=(-2+(-1),-20+(-10))
2v+u=(-3,-30)
but need to label (a), (b), and (c).

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