You can put this solution on YOUR website! Find the zeroes of ax^2+bx = y-c
By completing the square
---
y = ax^2 + bx + c = 0
Divide by a
x^2 + (b/a)x + c/a = 0
x^2 + (b/a)x = -c/a
Make left side a square by adding (b/2a)^2
x^2 + (b/a)x + b^2/4a^2 = -c/a + b^2/4a^2
