Question 1068730: Given:
A=? a= 6
B= 14.3 b= ?
C= ? c=25
Find A
A.)
B.)
C.)
D.) Found 2 solutions by Boreal, swincher4391:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! b^2=a^2+c^2-2ac cos B
=36+625=2(6)(25)cos 14.3
=661-290.70
=19.24
sin A/6=sin 14.3/19.24
sin A=6*sin 14.3/19.24
=0.0770
Arc sin 0.0770=4.42 deg
A
You can put this solution on YOUR website! Assuming we are talking about triangle ABC we have sides:
a which is opposite angle A
b which is opposite angle B
c which is opposite angle C
We have angle A that is in between sides b and c
We have angle B that is in between sides a and c
We have angle C that is in between sides a and b.
So since we have angle B that is in between sides a and c (and we know all three of these values), this lets us know that we can use the law of cosines.
So
We need to find angle A. So since we know side a, side b and angle B, we can use law of sines.
