SOLUTION: 1.) How many possible positive roots does {{{ 3x^3 + 4x - 12 }}} have?
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2.) How many negative roots does {{{ 3x^3 + 4x - 12 }}} have?
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-> SOLUTION: 1.) How many possible positive roots does {{{ 3x^3 + 4x - 12 }}} have?
None
One
Two
Three
2.) How many negative roots does {{{ 3x^3 + 4x - 12 }}} have?
None
One
Two
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Question 1053760: 1.) How many possible positive roots does have?
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2.) How many negative roots does have?
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Thank you Answer by Edwin McCravy(20054) (Show Source):
We use DeCartes' rule of signs:
The signs go + + -.
There is 1 sign change going left to right.
You can't subtract 2 from 1 and get a non-negative number,
so there is exactly 1 positive root.
Now we substitute -x for x
The signs go - - -
There are no sign changes going left to right.
You can't subtract 2 from 0 and get a non-negative
number, so there are exactly ZERO negative roots.
That is to say, there are NO negative roots.
Graphical justification:
Edwin
