SOLUTION: I need step by step instruction on how to solve this word problem; suppose a auto racer won a 500 mile race with a time of 1:48:33. At one point the racer was 60 miles closer to th

Algebra ->  Test -> SOLUTION: I need step by step instruction on how to solve this word problem; suppose a auto racer won a 500 mile race with a time of 1:48:33. At one point the racer was 60 miles closer to th      Log On


   

Question 1052974: I need step by step instruction on how to solve this word problem; suppose a auto racer won a 500 mile race with a time of 1:48:33. At one point the racer was 60 miles closer to the finish than the start. How far from the start was the racer?
Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.
auto racer won a 500 mile race with a time of 1:48:33. At one point the racer was 60 miles closer to the finish than the start.
How far from the start was the racer?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

First of all, the given time is not relevant to the question.

Now, the answer is 250 + 30 = 280 miles.
The racer was at 280 miles from the start.

Solution 

Let d be the distance under the question.
Then the distance to the finish is (500-d), and your condition says 

d - (500-d) = 60.

Simplify and solve:

2d - 500 = 60,

2d = 60 + 500,

2d = 560  --->  d = 560%2F2 = 280.

Solved.