SOLUTION: Liquid A has 10 grams of element X per liter. Liquid B has 15 milligrams of element Y per cm3 (there are 1000 milligrams in a gram and 1000 cm3 in a liter). It is desired to make 1

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Question 1052476: Liquid A has 10 grams of element X per liter. Liquid B has 15 milligrams of element Y per cm3 (there are 1000 milligrams in a gram and 1000 cm3 in a liter). It is desired to make 150 grams of molecule Z. To make 18 grams of Z requires 2 grams of X and 16 grams of Y. How many liters of each liquid should be used?
Answer by ikleyn(52754) About Me  (Show Source):
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Liquid A has 10 grams of element X per liter. Liquid B has 15 milligrams of element Y per cm3
(there are 1000 milligrams in a gram and 1000 cm3 in a liter).
It is desired to make 150 grams of molecule Z. To make 18 grams of Z requires 2 grams of X and 16 grams of Y.
How many liters of each liquid should be used?
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Liquid A has 10 grams of element X per liter.

Liquid B has 15 milligrams of element Y per cm3, or, which is the same,
             15 gram of element Y per liter.


To make 18 grams of Z requires 2 grams of X and 16 grams of Y, or, which is the same, 
                               0.2 liters of A and 16%2F15 liters of B.   (*)

150%2F18 = 8 1%2F3.

Therefore, the amounts (*) must be multiplied by 8 1%2F3 = 25%2F3 each.

So, you need 0.2%2A%2825%2F3%29 liters of A and %2816%2F15%29%2A%2825%2F3%29 liters of B.

Again: %282%2F10%29%2A%2825%2F3%29%29 = 50%2F30 = 5%2F3 liters of A,  and

       %2816%2F15%29%2A%2825%2F3%29 = 80%2F9 liters of B.

Solved.