SOLUTION: Q: For some constant α,the graph of a quadratic function f(x)= -x^2+2αx is a parabola with x intercept at A and B and vertex C.If the area of a triangle whose vertices ar

Algebra ->  Test -> SOLUTION: Q: For some constant α,the graph of a quadratic function f(x)= -x^2+2αx is a parabola with x intercept at A and B and vertex C.If the area of a triangle whose vertices ar      Log On


   



Question 1041002: Q: For some constant α,the graph of a quadratic function f(x)= -x^2+2αx is a parabola with x intercept at A and B and vertex C.If the area of a triangle whose vertices are A B and C equals 125,what is the value of α?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
So you can look at the parabola, in terms of its roots.
y=-x%28x-2%2Aalpha%29
So the roots occur at x=0 and x=2%2Aalpha to the base of the triangle which equals the distance between the roots is,
b=2%2Aalpha
So convert the parabola to vertex form,
y=-x%5E2%2B2%2Aalpha%2Ax
y=-%28x%5E2-2%2Aalpha%2Ax%2B%28alpha%29%5E2%29%2B%28alpha%29%5E2
y=-%28x-alpha%29%5E2%2B%28alpha%29%5E2
So the vertex is the maximum value of the parabola and the distance from the x-axis equals the height of the triangle governed by the term %28alpha%29%5E2.
The area of the triangle is,
A=%281%2F2%29bh
A=%281%2F2%292%2Aalpha%2Aalpha%5E2
alpha%5E3=125
alpha=5