SOLUTION: Divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4:3.

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Question 1040985: Divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4:3.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4:3.
:
Two parts a & b
a + b = 282
"the eighth part of the first and the fifth part of the second are in the ratio 4:3."
Using the decimal equiv, 1/8 = .125 and 1/5 = .200
%28.125a%29%2F%28.2b%29 = 4%2F3
cross multiply
4(.2b) = 3(.125a)
.8b =.375a
b = %28.375a%29%2F.8
b = .46875a
then
a + .46875a = 282
1.46875a = 282
a = 282%2F1.46875
a = 192
find b
b = 282-192
b = 90
:
The two parts are 192 and 90
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:
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See if this works
.125(192) = 24
.200(90) = 18
24/18 = 4/3