SOLUTION: Passing through (4,-8) and perpendicular to the line whose equation is x-5y=3
Write an equation for this line in point slope form:
Also
Write and equation for this line in
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-> SOLUTION: Passing through (4,-8) and perpendicular to the line whose equation is x-5y=3
Write an equation for this line in point slope form:
Also
Write and equation for this line in
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Question 1040715: Passing through (4,-8) and perpendicular to the line whose equation is x-5y=3
Write an equation for this line in point slope form:
Also
Write and equation for this line in slope-intercent form:
Please help Found 3 solutions by Boreal, josgarithmetic, ikleyn:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The line x-5y=3 may be written as 5y=x-3 or y= (1/5)x-(3/5), slope -intercept form. The slope of the line perpendicular to this line is the negative reciprocal of the coefficient of x. That is the negative reciprocal of (1/5). To find that, flip the fraction and change the sign. It is therefore -5.
point slope form of the line that goes through (4,-8) perpendicular to the line given has slope -5
y-(-8)=-5(x-4)
y+8=5(x-4) That is point-slope form
y=5x-20-8
y=5x-28 That is slope-intercept form.
Graph doesn't show x and y the same interval for each.
You can put this solution on YOUR website! The slope for the given line is and any line in the plane perpendicular to it will have slope . Perpendicular lines in a plane have slopes which are negative reciprocals.
Now the question is, what is the equation for a line passing through point (4,-8) and with slope ?
Using the point-slope form of equation, .
Simplify this and solve for y in terms of x. -------the same line but now in slope-intercept form.
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