Question 1037877: Let theta be an angle in quadrant IV such that sin(theta) = -8/9.
Find the exact values of sec(theta) and cot(theta)
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The sine is opposite over hypotenuse or -8/9
The other side must be the square root (17), so that the sum of the squares of the legs=square (hypotenuse)
That makes the cosine= +square root (17)/9, so the secant is 9*square root (17)/17, the reciprocal, after rationalization of the denominator.
The cotangent is cosine/sine, or sqrt(17)/9/-8/9, or - sqrt(17/8).
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