SOLUTION: John is 4 yrs older than Mary and Ainy is 2 yrs younger than Mary. If the sum of their ages is 41,how old will John be in 8 years' time?
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Question 1037846: John is 4 yrs older than Mary and Ainy is 2 yrs younger than Mary. If the sum of their ages is 41,how old will John be in 8 years' time? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! John is 4 yrs older than Mary and Ainy is 2 yrs younger than Mary. If the sum of their ages is 41,how old will John be in 8 years' time?
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J = M + 4
A = M - 2
J + M + A = 41
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Sub for J and A
M+4 + M + M-2 = 41
3M + 2 = 41
3M = 39
M = 13 (Mary's age now)
etc
