SOLUTION: ABCDEFGH is a regular octagon and AB=p and BC=q. Express AH in terms of p and q and show that AE+BH+CG+DF=2(2+√2)(q-V2 times p).
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-> SOLUTION: ABCDEFGH is a regular octagon and AB=p and BC=q. Express AH in terms of p and q and show that AE+BH+CG+DF=2(2+√2)(q-V2 times p).
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Question 1018079: ABCDEFGH is a regular octagon and AB=p and BC=q. Express AH in terms of p and q and show that AE+BH+CG+DF=2(2+√2)(q-V2 times p). Answer by ikleyn(52781) (Show Source):
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ABCDEFGH is a regular octagon and AB=p and BC=q. Express AH in terms of p and q and show that AE+BH+CG+DF=2(2+√2)(q-V2 times p).
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Your condition looks strange.
If ABCDEFGH is a regular octagon, then AB = p = BC = q = AH, as AB, BC and AH are the sides of the regular octagon.
