SOLUTION: In the expansion of (2+x)^14 multiplied by (1+2/x)^14, find the coefficient of x^12.

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Question 1013237: In the expansion of (2+x)^14 multiplied by (1+2/x)^14, find the coefficient of x^12.
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In the expansion of (2+x)^14 multiplied by (1+2/x)^14,
find the coefficient of x^12
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(2+x)^14*(1+(2/x))^14 = [(2+x)(1+(2/x))]^14 = [2+(4/x) + x + 2]^14
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= [x + 4/x + 4]^14
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etc.
Cheers,
Stan H.

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
In the expansion of (2+x)^14 multiplied by (1+2/x)^14, find the coefficient of x^12.
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Apply the binomial formula to expand %282%2Bx%29%5E14 and %281%2B2%2Fx%29%5E14. You will have 

%282%2Bx%29%5E14+%2A%281%2B2%2Fx%29%5E14 = %28sum%28+C%5B14%5D%5Ei%2Ax%5Ei%2A2%5E%2814-i%29%2C+i=0%2C14%29%29 * %28sum%28+C%5B14%5D%5Ej%2A%282%2Fx%29%5Ej%2A1%5E%2814-j%29%2C+j=0%2C14%29%29.

where C%5Bn%5D%5Em are the binomial coefficients. (See the lessons 
  Introduction to Combinations  and 
  Binomial Theorem, Binomial Formula, Binomial Coefficients and Binomial Expansion 

in this site).

Now, when you open parentheses, cross-multiply the terms as it is required and collect the common terms, 
you will see that x%5E12 comes from these and only from these terms:

C%5B14%5D%5E14%2Ax%5E14%2A2%5E0 * C%5B14%5D%5E2%2A%282%2Fx%29%5E2 + 

+ C%5B14%5D%5E13%2Ax%5E13%2A2%5E1 * C%5B14%5D%5E1%2A%282%2Fx%29%5E1 +

+ C%5B14%5D%5E12%2Ax%5E12%2A2%5E2 * C%5B14%5D%5E0%2A%282%2Fx%29%5E0.


Thus the coefficient at x%5E12 will be


C%5B14%5D%5E14%2A2%5E0 * C%5B14%5D%5E2%2A2%5E2 + C%5B14%5D%5E13%2A2%5E1 * C%5B14%5D%5E1%2A2%5E1 + C%5B14%5D%5E12%2A2%5E2 * C%5B14%5D%5E0%2A2%5E0.

Next substitute here  2%5E0 = 1,  C%5B14%5D%5E0 = 1,  C%5B14%5D%5E14 = 1, calculate the rest of binomial coefficients and get the answer. 

My part is to give you the general idea and the pivotal direction.
The rest is on you.