SOLUTION: An object is moving in a straight line. The distance (in meters) from a fixed point is given by s= -2t^3 - 4t^2 + 6t + 4 where t≥0. Determine the acceleration when the veloci
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-> SOLUTION: An object is moving in a straight line. The distance (in meters) from a fixed point is given by s= -2t^3 - 4t^2 + 6t + 4 where t≥0. Determine the acceleration when the veloci
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Question 1006618: An object is moving in a straight line. The distance (in meters) from a fixed point is given by s= -2t^3 - 4t^2 + 6t + 4 where t≥0. Determine the acceleration when the velocity is -2m/s Answer by ikleyn(52748) (Show Source):
The procedure is as follows:
1. Take the derivative of s by t.
You will get a quadratic polynomial of t for the velocity, v(t) = .
2. Solve the quadratic equation v(t) = -2 to find the time moment when the velocity is - 2 .
3. Take the second derivative of s by t to get the expression for the acceleration a(t).
4. Substitute the found value of t into the expression for acceleration to determine the unknown acceleration.
Good luck!
