SOLUTION: The perimeter of a rectangle is 482cm. The length is 6cm greater than 4 times the width. Find the length
Algebra
->
Test
-> SOLUTION: The perimeter of a rectangle is 482cm. The length is 6cm greater than 4 times the width. Find the length
Log On
Test Calculators and Practice
Test
Answers archive
Answers
Word Problems
Word
Lessons
Lessons
Click here to see ALL problems on test
Question 1002430
:
The perimeter of a rectangle is 482cm. The length is 6cm greater than 4 times the width. Find the length
Answer by
larryblackwell(1)
(
Show Source
):
You can
put this solution on YOUR website!
L=6+4x,w=x,~P=2L+2W~ 482=2[6+4x]+2x~ 482=12+8x+2x ~ 482=12+10x ~ 482-12=12-12+10x ~470=10x ~ 470/10=10x/10 ~ 47=x : L=6+4[47]~ L=6+188 therefore L=194cm.